Instantiate an interface?

[Stan Forest]

Can an interface can be instantiated in an anonymous class? Does this code have an instance of an interface?
// From Kathy Sierra's book page 471
interface Cookable {
public void cook();
}
class Food {
Cookable c = new Cookable(){ // instantiates an interface
public void cook() {
System.out.println("Anonymous cookable implementer");
}
};
}
public class Test {
public static void main(String arg[]){
Food f = new Food();
f.c.cook();
}
}
I bring the question up because of Marcus Green's Mock Exam 2 Question 57.

[Barry Gaunt]

Nope. What it's doing is instantiating a subclass of Object which happens to implement the Cookable interface. It's an anonymous class instance.

[Corey McGlone]

This code doesn't really instantiate an interface. What it does is creates an object that implements the interface. Because the object implements that interface, it must provide implementations for all methods defined within that interface - in this case, the cook() method.
I hope that helps,
Corey

[sharana sharana]

Cookable c = new Cookable(){ // instantiates an interface
public void cook() {
System.out.println("Anonymous cookable implementer");
}
};
this code does create an anonymous class which implements the interface cookable. and stores the reference of the same in to interfaces reference variable C [ perfectly valid widening reference conversion ]
hope that would helps