Nice Question

[Lawrence Chettiar]

public class TestChar
{
public static void main(String[] args)
{
byte A = 1;
byte B = \u0041; // 1
System.out.println(B);
}
}
What happens when we compile and run this code
1. prints 65
2. prints 1
3. gives compiler error at line marked 1
4. runtime exception at line 1 cannot assign char to byte variable

[Charles Leung]

it prints 1
since unicode is converted in very early stage of compilation
the line
byte B = \u0041;
becomes
byte B = 1;
and hence the answer

[Jerry Volo]

this would be true if \u0041 was really '1'.
Actually it is the character 'A' and therefore will give a compiler error. The value for '1' is really \u0031!

[donald rieck]

Is the real question, "will unicode implicitly convert to a byte?"

[GM Shobha]

public class TestChar
{
public static void main(String[] args)
{
byte A = 1;
byte B = \u0041;
System.out.println(B);
}
}

The above code compiles and prints 1. But I noticed that if the value of �A�
(can vary from �128 to 127) changes, printed value of B also changes accordingly ie the printed value of B is exactly same as the value of variable �A�.
Actually B has Unicode value that represents character A (\u0041) & byte variable A is referring to value 1 & this is the value printed for variable B.
However if byte B is assigned Unicode value of numbers (0 to 9) ie from \u0030 to \u0039, it prints the no.s 0 to 9 correspondingly.

The same thing happens in following cases.
byte B =3;
byte x=\u0042; // as this represents Unicode value of letter B
System.out.pritln(x); //prints 3
byte Z=8;
byte x=\005A; // this represents Unicode value of Z
System.out.pritln(x); //prints 8
This is true for letters from A to Z with Unicode value ranging from \u0041 to \005A & a to z with Unicode values ranging from \0061 to \007A.
Why is this happening here?

[Jose Botella]

The compiler translates Unicode escapes to the corresponding Unicode characters.

byte Z=8;
byte x=\005A; // this represents Unicode value of Z
System.out.pritln(x); //prints 8

\u005A is translated to the variable Z, and thus Z is assigned to x , and its value is printed.
_________________________________________________
By the way, Welcome to the Ranch Jerry and GM.
[ April 24, 2003: Message edited by: Jose Botella ]

[Julian Reed]

I'm confused.
When using the JDK 1.4, if I try to compile this:
int q=\u0041;
it complains it can't resolve the symbol.
If I use Visualage for Java, it compiles. Any ideas why the JDK does not work?
Thanks
Julian

[Thomas Paul]

Originally posted by Julian Reed:
If I use Visualage for Java, it compiles. Any ideas why the JDK does not work?

This compiles cleanly in JDK 1.4:

public class UniTest {
    public static void main(String[] args) {
        byte A = 8;
        byte b = \u0041;
    }
}