Hello,
I am totally confused with operator precedence.
It is said that expr++ has higher precdence than ++expr
link.
What does this mean?
Let me come down to 2 questions with examples
1.
int x = -1;
int y = ++x + x++;
Will the above line be executed as 1 + -1 = 0
or as 0 + 0 = 0. Because when i try to execute it i will always get the answer as 0 but i don't know which is first evaluated is it ++x or x++. please help!!!
2. Unary operators are evaluated in right to left order. What does this mean...
y = x+++x;
is it equivalent to (x++) + x or x + (++x) .
The answer is same in both cases.
I hope I am clear in my questions.
Thank you
Lalitha