I think the answer should be d, but correct ans is c?? I was under impression that if you have argumented construtor you "must" also have default construtor defined, since it is provided implicitly. Any missing part for me? Advannce Thanx -PC
Hai Priyanka, The answer is c. Your assumption (answer d) would have been correct if the Bclass constructor did not call super(3). Say, the Bclass constructor has simply been omitted or has nothing in its body, then a no-argument super class constructor would have been called by default as you said.
The choice would be d for this case : class AClass { static int x; AClass(int x) { this.x = x; } } public class BClass extends AClass { BClass() {} // or if this line has been commented out. public static void main(String[] args) { BClass BC = new BClass(); System.out.println(x); } } Hope this helps.
Even for this case you'll get a compile time error because there is no constructor in Aclass that accepts no arguments. BClass() { super(); } In your program, you are safe since a matching super class constructor is called in Bclass constructor. [ October 15, 2003: Message edited by: Kalai Ganesh ]
Hello, I have a question that is a subclass can extends a static variable from superclass? I know a static variable is shared by all object, but it can share by an instance of subclass?
I am really appreciate it.
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