Need Help on More Anonymous Classes

[dennis zined]

Hello.
In the code below, why is it that the overridden methods method1 and method2 never gets called and the original methods are executed instead? However, changing all the private access modifiers to public access enables the overridden methods to be called instead of the original methods?
Any insights/info is greatly appreciated. Thanks.

  
public class SomeAnonymous {
    public SomeAnonymous() {
        super();
    }
    public static void main(String[] args) {
        new SomeAnonymous().method3();
    }
    private void method1(){
        System.out.println("nothing");
    }
    private void method2(){
        System.out.println("nothing");
    }
    private void method3(){
        SomeAnonymous someanonymous = new SomeAnonymous(){
            private void method1(){
                System.out.println("method 1");     // overrides method1()
            }
            private void method2(){
                System.out.println("method 2");     // overrides method2()
            }
        };
        someanonymous.method1();            // calls original method
        someanonymous.method2();            // calls original method
    }
}

[Uma Balu]

Hi,
Is it because the methods defined inside the anonymous class are private and can be called within the anonymous class only?? (ie. the methods are not visible in the context where it is defined, since they are private)
Uma.

[Steve Lovelace]

private methods cannot be overridden. In fact, outside of the class in which they are defined, they simply don't exist (and therefore can't be overridden) - even subclasses don't know about them.
Your anonymous class is a subclass. It's redeclaration of the private methods does not override them. Hence the behavior.

[dennis zined]

Got it. Geesh, there's just so many things to keep in mind. Thanks again Steve