A Question on Postfix Operator...

[Sripada Phani]

I have writeen the below code to test post fix operator.
public class OpsTest {
public static void main(String a[]) {
int i=2,j=2,k=3;
i=i++ + k;
j=j + k;
System.out.println("i= "+i+" j="+j);
}
}
I expected the value of i would be printed different from j. To my surprise I got both i and j values printed same. Can anyone explain me why the post fix operator was ignored in the first case.

[Vicken Karaoghlanian]

hi Sripada, and welcome to the ranch.
The trick is with this statement.

  i=i++ + k;

you might suspect that it is evaluated like this 'i = 3 + 3 ', but it is actually evaluated 'i = 2 + 3'. You ask why?

public class Test {
public static void main(String[] args) {
int i = 0;

System.out.println(i++);
System.out.println(i);
}
}

Hope this helps.
[ December 02, 2003: Message edited by: Vicken Karaoghlanian ]

[prasanthi alla]

hi sripada!
the postfix operator is not neglected,see the steps how's it executed
for the code i=i++ + k
i=2+3 ( now i is incremented to 3 ,so now i= 3)
i=5 ( now i is assigned the value of 5)
so finally i got the value of 5
bye
prasanthi