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Increment operator in assignment

 
Selvakumar Arumugam
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Anybody please explain what is happening here?
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int i =0;
i = i++;
i = i++;
i = i++;
System.out.println(i);
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I was expecting i to be 3. But it's printing 0.
 
Vicken Karaoghlanian
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Hi Selvakumar and welcome to the ranch, the post increment operator always returns its old value then increment it.
 
Thomas De Vos
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The reason is that the ++ operator is a postfix operator.
You can read x++ also as x = x = (x+1)
This means that the value of x in your case 0 is first assigned to x and then incremented. The value is incremented after the assignment operation.
The second time around the value of i will be still 0 and then assigned first and incremented etc.
 
Selvakumar Arumugam
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Vicken and Thomas Thanks for the reply. I am clear about it.
Thanks!
 
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