Math class

[Harsha Vardhan Madiraju]

hi all,
Can anyone explain me how the below comparison is true or returns true
Math . round ( Integer . MIN_VALUE - 6.5f ) == Integer . MIN_VALUE
Thanx in advance

[Donny Nadolny]

It has to do with what data a float can hold - it can hold 1.4E-45 to 3.4E38, which means that there are certain values it cannot hold which are in between those values.
For example, Math.round(99.499999f) = 100. You and I can see that when you round that number it should be 100, but a float can't hold the exact number 99.499999 and the closest number that it can see is 99.5 something. Hope this helps (I don't believe the SCJP expects you to know the rounded (integer or long) value of any float or double value). Hope this helps.

[Sriram Chintapalli]

Hi Harsha,
Math . round ( Integer . MIN_VALUE - 6.5f ) == Integer . MIN_VALUE
returns true because an integer can hold a minimum number -2 power of 31. Here we are rounding a value that actually should return Integer.MIN_Value-6 but an integer cannot hold such a small value so it rounds it to its minimum value Integer.MIN_VALUE. This behavior is symmetric and when we round a value that is more than Integer.MAX_Value it automatically rounds it to Integer.MAX_VALUE (ie) System.out.println(Math.round(Integer.MAX_VALUE + 1.5f)==Integer.MAX_VALUE); is true.
And yes sire in case you were wondering this is the same with Long also
System.out.println(Math.round(Long.MAX_VALUE + 1.5)==Long.MAX_VALUE);
returns true.
Hope this helps.
sriram

[Donny Nadolny]

Here we are rounding a value that actually should return Integer.MIN_Value-6 but an integer cannot hold such a small value so it rounds it to its minimum value Integer.MIN_VALUE

I don't believe that it's because an integer can't hold a small value - see the output from the following code:

System.out.println(Integer.MIN_VALUE - 1);

The output will be a very large number (2.19 billion approx) because Java's numbers are signed - when you try to go too low, they loop around to be positive. I believe the answer to the question is the response I gave previously .

[CH Lee]

Hi guys,
This is a very interesting topic. I did some testing with all the listed code and found this on API documentation.

 
Special cases: 
* If the argument is NaN, the result is 0. 
* If the argument is negative infinity or any value less than or equal to the value of Integer.MIN_VALUE, 
  the result is equal to the value of Integer.MIN_VALUE. 
* If the argument is positive infinity or any value greater than or equal to the value of Integer.MAX_VALUE, 
  the result is equal to the value of Integer.MAX_VALUE.

Hope this helps us understand it better.
Cheers.
[ February 10, 2004: Message edited by: CH Lee ]