Conditional Operators (try this)

[Suresh Thota]

  
class ConditionalCheck {
  static boolean a, b, c;
  public static void main (String[] args) {
    boolean x = a=false || (b = true) && (c = true);
    System.out.print(a + "," + b + "," + c);
}}

What is the output?
Cheers
-Suresh

[Vineela Devi]

Hi suresh,
i think the ans is true, true, true.
Vineela

[Thomas De Vos]

Step by step
boolean x = a = false || (b = true) && (c = true);
1. b and c becomes true
boolean x = a = false || (true) && (true);
2. (true) && (true) is true
boolean x = a = false || true;

3. false || true is true
value of a is set true
value of x is set to true
So the answer is indeed true, true, true

[Vicken Karaoghlanian]

Thomas explanation is clear, however I want to add one more thing...
if boolean x = a=true || (b = true) && (c = true);
then "(b = true) && (c = true)" is never evaluated thus outputting.
true false false.

[Shilpi M Agarwal]

Vicken
Your point is correct but when u actually excute the code the ans is true,true,true!
And now i am confused!
Shilpi

[Vicken Karaoghlanian]

Evaluating
1) boolean x = a=true || (b = true) && (c = true);
will result: true, false, false
2) boolean x = a=false || (b = true) && (c = true);
will result true, true, true

I think you simply misread the question, am I right?

[Abdulla Mamuwala]

The concept is:
The && operator has precedence over the || operator.
Lets apply this concept to your expression:
boolean x =a=false||(b = true) && (c = true)-------[1]
Step 1
&& is evaluated before || giving,
(b=true)&&(c=true)
The Result being true
Both sides of the above expression will be evaluted giving,
b=true and c=true
Step 2
next, || is evaluated giving,
a=false||true
The result being true
Now try interchanging the || and && in the expression [1] above,
The output will be,
true false true
The concept being the same.

[Dan Andrei]

Vicken:
"
if boolean x = a=true || (b = true) && (c = true);
then "(b = true) && (c = true)" is never evaluated thus outputting.
true false false."

this is wrong... && has higher precedence over ||, so the assg to b and c
are made because of this and the answer is true true true

[Narasimha Rao B.]

Hi,
Why the output of the below one is - true, false, false.
-----
class ConditionalCheck {
static boolean a, b, c;
public static void main (String[] args) {
boolean x = a=true|| (b = true) && (c = true);
System.out.print(a + "," + b + "," + c);}}
---------
If && has higher precedence than ||, why (b=true) && (c=true) is not evaluated.
I am bit confused, please explain.

Narasimha.

[Dan Andrei]

first I want to apologize to Vicken for my prevoius post,
HE WAS RIGHT AND i WAS WRONG
I think the result is true false false, because of the rules of evaluation of && and || ops.
Now IF the left hand side of the || op is true then the rest is not evaluated regardless id we have && (higher order evaluation op)
In the example x=a=false||(b=true)&&(c=true)
BECAUSE the left hand side was FALSE we have to evaluate the rigth hand side
and here because && had higher precedence it was evaluated first

[Vicken Karaoghlanian]

Originally posted by Dan Andrei:
first I want to apologize to Vicken for my prevoius post,
HE WAS RIGHT AND i WAS WRONG
I think the result is true false false, because of the rules of evaluation of && and || ops.
Now IF the left hand side of the || op is true then the rest is not evaluated regardless id we have && (higher order evaluation op)
In the example x=a=false||(b=true)&&(c=true)
BECAUSE the left hand side was FALSE we have to evaluate the rigth hand side
and here because && had higher precedence it was evaluated first

I couldn�t explained it better... Way to go.

[Ransika deSilva]

boolean x = a=true || (b = true) && (c = true);
System.out.println(a + "," + b + "," + c);
boolean x = a=true && (b = true) || (c = true);
System.out.println(a + "," + b + "," + c);
Hello all,
I am preparing for the SCJP exam. I am confused with the concept discussed here. Looks like according to the question posted, precedence doesn't make any difference. It is true, if the two operators have the same level of precedence, it is evaluated from left to right. But here the && operator has higher precedence over the || operator, so the expression should be evaluated in a hierarchical order.Which means the && operator should be evaluated first and then the || operator. But it seems like in both the situations it is evaluated from right to left. So could you please explain what is happening here.
Thank you very much.....