why there is no unreachable compile error ?

[Raju Sri]

Hi ,
The below code compiles and run without any problem.
public class Test
{
public static void main(String args[])
{
System.out.println("A");
try
{
return; // line1
}
catch(Exception e)
{
System.out.println("B");
}
System.out.println("C"); // line2
}
}
Why the above code compiles when //line2 is not reachable . why it doesn't give unreachable statment error at the time of compilation ?
Raju

[Ernest Friedman-Hill]

If line 1 throws an exception (as far as the compiler is concerned, it might throw an unchecked one) then the catch block recovers and line 2 will execute.