String objects

[Ramnath krishnamurthi]

Hi,
The below code creates 4 String objects

String s1 = �Hello�;--(1)
String s2 = s1;--(2)
s1 = s1.concat(�World�);--(3)
s2.concat(�!!!�);--(4)
  

Correct me if am wrong.
Thanks,
Ramnath

Feed an Opportunity.Starve a Problem

[sameer kumar]

posted by ramnath
------------------------
String s1 = �Hello�;--(1)
String s2 = s1;--(2)
s1 = s1.concat(�World�);--(3)
s2.concat(�!!!�);--(4)
-----------------------------------
u r wrong dear :
here only three string object are created
At line 1
at line 3
at line 4
line 2 s2 pointed the same objected created at line i
bcoz this strings object r created in literial pool
if the same string availlabe in the pool then Jmn not going to created new string object
ok
whatever i know i have written
it may be this is usefull for u
sameer kumar

[Ramnath krishnamurthi]

Sameer,
Yup.You are right.s2 simply points to s1 and no new String object is getting created because of the assignment.
Thanks,
Ramnath

Feed an Opportunity.Startve a problem

[chris anderson]

Hi guys!
The question was: how many String objects were created alltogether and I certainly disagree with sameer's 3.
Because...
String s1 = �Hello�; //creates 1st one
String s2 = s1; // no new objects
s1 = s1.concat(�World�);
//create "World" and "HelloWorld" objects. "World"
//is lost but s1 is referring now to "HelloWorld"
//so 2nd and 3rd objects are created
s2.concat(�!!!�); //4th object's created but it lost at once
So 4 objects alltogether is how I undertand it?

[chris anderson]

sorry!
5 objects
if we are to follow the logic
explained in the previous reply!!!

[Karthik Gurunathan]

How about this one ?
String x=new String("abc")
How many objects will be created in the above statement..I thought it will create only one object..but K&B says 2 ..
please explain

[Corey McGlone]

The answer to the original queston is 5. Each of the strnig literals causes a String object to be created and the two invocations of concat create new String objects.
To answer Karthik's question, when you have a line of code like this:

String s = new String("test");

You are really creating 2 String objects. First of all, the String literal, "test," causes a String object to be created when the class is loaded (the String literal is treated as a constant). Then, when we invoke the constructor of the String class and pass it that literal, we are creating a second String object.
So what's the best news in all of this? None of this is on the exam.