Overriding static methods - pl explain!

[Sridhar Srinivasan]

class BaseClass{
static void sayHello(){
System.out.println("Hi pal!!!, I am BaseClass");
}
}

public class MyFor extends BaseClass{
static void sayHello(){
System.out.println("Hi pal!!!, I am SubClass");
}

public static void main(String [] arg){
BaseClass bc = new MyFor();
bc.sayHello();
}
}
I thought that the answer for the above is "Hi pal!!!, I am SubClass" but the answer which is given is "Hi pla!!!, I am BaseClass". Can anybody explain please?Thanks

[Corey McGlone]

Try this.

[Gauri Savanur]

Static and overloaded method invokation is decided at compile time and not at run time.
So even if the object is of subclass type, the method invokation is dependent on reference.