char literals
public static void main (String[] args) {
char a = 061; // 1
char b = '\61'; // 2
char c = '\061'; // 3
char d = 0x0031; // 4
char e = '\u0031'; // 5
System.out.print(""+a+b+c+d+e);
}}
A compile-time error is generated at which line?
a. 1
b. 2
c. 3
d. 4
e. 5
f. None of the above
Answer: f (None of the above)
Reason given :
All of the declarations are legal. The first three ( 061, '\61', '\061' ) are declared in octal format. The fourth (0x0031) is declared as a hexadecimal literal. The fifth ('\u0031') is a Unicode escape sequence.
061 is a valid char literal.Its in octal format.
But is '\061' and '\61' in octal format?
Can anyone justify how '\61','\061' are valid char literals.
What are the various Unicode escape sequences ?
Thanks in advance,
regards,
rajani.
According to JLS one of the Escape sequence type are using octal literals.
There are three formats of Octal Escape sequences.
1) \octaldigit
2) \octaldigit octaldigit
3) \zerotothree octaldigit octaldigit
For more information on EscapeSequence refer JLS @ http://java.sun.com/docs/books/jls/second_edition/html/lexical.doc.html#101089
By the way I dont know how much we need to cover for SCJP 1.4
Regards
Anuradha<br />(SCJP 1.4)
Originally posted by rajani sudhakar:
class MCZ24 {
public static void main (String[] args) {
char a = 061; // 1
char b = '\61'; // 2
char c = '\061'; // 3
char d = 0x0031; // 4
char e = '\u0031'; // 5
System.out.print(""+a+b+c+d+e);
}}
A compile-time error is generated at which line?
a. 1
b. 2
c. 3
d. 4
e. 5
f. None of the above
Answer: f (None of the above)
Reason given :
All of the declarations are legal. The first three ( 061, '\61', '\061' ) are declared in octal format. The fourth (0x0031) is declared as a hexadecimal literal. The fifth ('\u0031') is a Unicode escape sequence.
061 is a valid char literal.Its in octal format.
But is '\061' and '\61' in octal format?
Can anyone justify how '\61','\061' are valid char literals.
What are the various Unicode escape sequences ?
Thanks in advance,
regards,
rajani.
