String consant pool

[K Anshul]

 public class Test { 
 
public static void main(String sg[]) { 
  
String s1 = new String("amit");
System.out.println(s1.replace('m','r'));
    System.out.println(s1);
String s3 = "arit";
String s4 = "arit";
String s2=s1.replace('m','r');
    System.out.println(s2==s3);
    System.out.println(s3==s4);
  } 
}
 

It gives the output
arit
amit
false
true

Why doesn't it give the output
arit
amit
true
true


Because it's giving false does it mean s2 is not refering to the string already in the String constant pool called "arit".
Why does it create a new object when String "arit" already exists.

[arnel nicolas]

The line String s2=s1.replace('m','r'), this actually creates a new object in the heap.It means that s2 now is pointing on a different object.When you are going to use the == for comparison it will compare both operands via their reference type. It is another story if you are going to use the equal operator(s2.equals(s3) which will turn out true.Both operands
are compared by their value.

arnel

[arnel nicolas]

Another thing, String are immutable. So if you you use any
of its methods it actually creates another String object.

arnel

[Corey McGlone]

And none of this is on the exam.

[K Anshul]

Originally posted by Corey McGlone:
And none of this is on the exam.

Nice to know that