Question on toBinaryString()

[vinayak manda]

class XYZ {
public static void main(String args[]) {
int j=017;
int i=(byte)j>>2;
System.out.println(Integer.toBinaryString(i));
}
}

Answer is 11,but I was expecting it as 00000011,
Can anyone please explain this.

[Corey McGlone]

Well, if one was to take a quick look at the API Spec for Integer, one might find this in the description of toBinaryString:

Returns a string representation of the integer argument as an unsigned integer in base 2.

The unsigned integer value is the argument plus 232 if the argument is negative; otherwise it is equal to the argument. This value is converted to a string of ASCII digits in binary (base 2) with no extra leading 0s. If the unsigned magnitude is zero, it is represented by a single zero character '0' ('\u0030'); otherwise, the first character of the representation of the unsigned magnitude will not be the zero character. The characters '0' ('\u0030') and '1' ('\u0031') are used as binary digits.

[ August 19, 2004: Message edited by: Corey McGlone ]