This week's book giveaway is in the Artificial Intelligence and Machine Learning forum.
We're giving away four copies of TensorFlow 2.0 in Action and have Thushan Ganegedara on-line!
See this thread for details.
Win a copy of TensorFlow 2.0 in Action this week in the Artificial Intelligence and Machine Learning forum!
  • Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other all forums
this forum made possible by our volunteer staff, including ...
Marshals:
  • Campbell Ritchie
  • Liutauras Vilda
  • Paul Clapham
  • Bear Bibeault
  • Jeanne Boyarsky
Sheriffs:
  • Ron McLeod
  • Tim Cooke
  • Devaka Cooray
Saloon Keepers:
  • Tim Moores
  • Tim Holloway
  • Jj Roberts
  • Stephan van Hulst
  • Carey Brown
Bartenders:
  • salvin francis
  • Scott Selikoff
  • fred rosenberger

final modifier

 
Ranch Hand
Posts: 42
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
I've done the following question,
but I don't understand why the answer is "d".
Could anyone explain it?
Thanks a lot.

class JSC201 {
static byte m1() {
final char c1 = '\u0001';
return c1; // 1
}
static byte m2(final char c2) {return c2;} // 2
public static void main(String[] args) {
char c3 = '\u0003';
System.out.print(""+m1()+m2(c3)); // 3
}}

What is the result of attempting to compile and run the program?

a. Prints: 13
b. Prints: 4
c. Compile-time error at 1
d. Compile-time error at 2
e. Run-time error
f. None of the above
 
Greenhorn
Posts: 19
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
Hey Grady,

If u check line 1...
return c1;
an implicit cast is put there 2 convert char to byte.
this is because c1 is a compile time constant...
(its value is known at complie time ie final char c1='\u001')

but in the case of line 2...
there is a problem cause c2 is not a compile time constant...
it is a definately a constant, but its value is not known at
compile time.. as it is an argument to a method its value can
change therefore the compiler complains at line 2.
 
Grady Jamyson
Ranch Hand
Posts: 42
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
I got it. Thanks a lot.
 
Ranch Hand
Posts: 7729
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
Stoneds Brains please read the JavaRanch Naming Policy and change your displayed name accordingly.

Thanks
-Barry
 
I'd appreciate it if you pronounced my name correctly. Pinhead, with a silent "H". Petite ad:
Building a Better World in your Backyard by Paul Wheaton and Shawn Klassen-Koop
https://coderanch.com/wiki/718759/books/Building-World-Backyard-Paul-Wheaton
reply
    Bookmark Topic Watch Topic
  • New Topic