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Queston on exceptions

 
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public class A{
void method(){
try {
meth();}catch (RuntimeException e){}
catch (Exception e){}
}
}
void meth(){

throw new RuntimeException()
}
}


will this code compile??
 
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No, but that would have been easy enough to test. The following does compile:


Is there a question here you are looking for an answer to?
 
Sandya Bhaskara
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here...meth()doesn't throw any checked exceptions..and method() is catching the only runtime exception that meth() throws..so why doesn't the compiler give an error?- catching an exception(here---catch (Exception e)) that has never been thrown??any exception that isnt a checked exception is a runtime exception...and that is caught by the code..so is it ok to catch Exception again??am i clear?
 
Greenhorn
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In my opinion, it should compile just fine.


It doesn't seem to violate any of the exception rules. You must declare that a method "throws" exception or provide a catch clause for it only if it is checked exception. RuntimeException and its subclasses are considered unchecked.
 
Chris Allen
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It won't compile without adding a semicolon the following line:
throw new RuntimeException()

but I don't think that is the answer you were really looking for...
 
Sandya Bhaskara
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nopes..its not the semicolon thing......that was a typo...
 
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Beside the semicolon typo Chris mentioned, there is an extra bracelet on line 6 that should be removed.

The modified code should look like this



You may want to use proper indentation next time in order to make your code more clear and readable, consider also using the [code] tags.
 
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