while() question

[PETER CARTER]

Given:
11. for( int i = min; i <max; i++) {
12. System.out.println(i);
13. }

If min and max are arbitrary integers, what gives the same result?
A. init i = min;
while( i < max ) {
}
B. int i = min;
do
System.out.println(i++);
} while( i< max );
C. for (int i=min; i<max; System.out.println(++I));
D. for (int i=; i++<max; System.out.println(i));
Answer: B

But I don't think here has correct answer .Do you follow me ?
I think the answer B is wrong ,when max<min.

[Piyush Jain]

when max<min the code snippet given in the question will not run by itself, so you have to make that assumption that max>min.

so B is the right answer.

Also, A can't be the answer because its not printing anything.

C is wrong because its printing I not i

D is wrong because i is not initialized to anything and will give a compiler error.

[vydhehi paruchuri]

B cannot be right answer since do while loop is executed atleast once irrespective of MIN and MAX valud but taht is not true for loop .

Vydhehi

[James Chegwidden]

Peter, your thinking to much into the question here.

This question is checking to see if you can rewrite the loop using something other than a for loop to be equivalent(i.e translate from one to another.)Also, remember how to always 1. initalize 2. test and 3. update the loops.

Now look at the questions:

Is A equivalent to the question? No, missing print statement
Is C equivalent to the question? No, because it will print nothing(notice the semicolon after the for)
Is D equivalent to the question? No, the update is wrong.

B is correct. the code could be rewritten as:

int i = min;
do
{
system.out.println(x)
x++;
}while(i < max);

which is the sam as the for loop.

[Louie van Bommel]

[ September 13, 2004: Message edited by: Louie van Bommel ]

[Jimmy Praet]

I believe the answer should be A, but with the print statement inserted ofcourse

for(initializers; condition; iteration)
{
  statements;
}

Is the same as

initializers;
while(condition)
{
  statements;
  iteration;
}

imho. The do.. while is incorrect because it is guaranteed to be executed at least once, the for loop isn't.

[PETER CARTER]

If it can compile successfully,it will be max>min.
So the answer is B.
Thanks .

[Jimmy Praet]

Why would it not compile if max<min?

If max and min were compile time constants then maybe it would not compile because of unreachable statements, but this isn't the case in the question so..

if max = min or max < min then B is not correct