is getting me confused

[vinayak manda]

 
class MWC114 {
  public static void main(String[] s) {
    String s1 = new String("ABCDEFG"), s2 = new String("EFGHIJ");
    String s3 = s1.substring(4,7), s4 = s2.substring(0,3);
    System.out.println((s3 == s4) + "," + (s3 + s4).equals(s4 + s3));
}}

[vinayak manda]

I'am sorry, I couldn't post the question before...

The question is when String s3 gets the value "EFG" and later s4 also gets the value "EFG", as the literal goes into the string pool,then s3 and s4 should point to the same reference.
Then why should (s3 == s4) return false.

Please clear this doubt.

[Barry Gaunt]

s3 gets a reference to a new String("EFG") and s4 gets a reference to another new String("EFG"). So s3 and s4 refer to different objects. Therefore s3 == s4 results in false.

[Ilja Preuss]

Only String literals go into the pool by default. You can use the intern() method for the others to enforce them to get into the pool, too.