switch Q

[Nitin Bhagwat]

In this code, i and j are of different type. As per switch rule, both should be of same type.

Why code is not giving error?
Thanks in advance.

 
public class Test001 
{
   public static void main(String args[]) 
   {
      char i = 'c';
      final int j = 100;  //1
      switch(i)       //2
      {
        default:         
        case 'c': break;
        case j:break;
      }
   }
}
 
 

[Pradeep bhatt]

from JLS

Every case constant expression associated with a switch statement must be assignable (�5.2) to the type of the switch Expression.

Now j whose value is 100 is assignable to char type.

For e.g

char c =100 work fine.

[Barry Gaunt]

Does it still work when j is not final? (try it)

[Nitin Bhagwat]

Nice try Barry,
i was aware that, case statement do not accept variable, it must be a constant. As expected, when j is not final, it is giving compiler error.