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Varargs in Tiger

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Here are my notes about varags in Tiger:

1- Defition:
void m1(T1 p1, T2... p2) {// use p2[]}

2- At most one vararg and as the last

3- An array can be passed when a vararg is expected.

4- To avoid this automatic conversion
of arrays cast them:
f(Object...) {}
T[] t;
f(t) --> f(t[0], t[1], ...)
f((Object)t)--> f(t)


5- f(S, T...) conflicts with f(S, T[]), can't be defined together.

6- f(S, T, T...) doesn't conflict with f(S, T...)
However, only the following calls are allowed:
f(s); // the second
f(s, t[]); // the second
f(s, t, t[]); // the first
while the following are not
f(s, t)
f(s, t, t)
f(s, t, t, t) and so on

7- f(S, T...) doesn't conflict with f(S, T): f(s, t) resolves to the

latter, and other calls (for 0 or 2 or more t paramters) to the former

8- In general f(S, T...) doesn't conflict with f(S, T, T, T): the

latter reserves the call with 3 T parameters and the former reserves

the rest.

9- A call is resolved first in favor of the exact parameters-count

match then in favor of best type match.

A <|-- B <|-- C

f(A), f(B...b):f(new B()) resolves to f(A)
f(A...a), B(B...b): f(new C()); resolves to f(B...b)

10- This has nothing to do with varargs:
if B extends A and implements I then the call is ambiguous:
f(A), f(I): f(new B()); it needs A cast to determine!

11- f(int...), f(double...) doesn't conflict, but f(i,j,..) is
- Ambiguous if all params are integrals or integral literals.
- Matchs the latter if one parameter is a double or a double literal.
The only way to invoke the former is f(int[]);
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