Win a copy of Programmer's Guide to Java SE 8 Oracle Certified Associate (OCA) this week in the OCAJP forum!
  • Post Reply
  • Bookmark Topic Watch Topic
  • New Topic

Math.sqrt

 
kundan varma
Ranch Hand
Posts: 323
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
HI All
can somebody tell me what is the logic behind such output:
System.out.println("Math.sqrt( -9.0 ) \t" + Math.sqrt( -9.0 ) );
System.out.println("Math.sqrt( -0.0 ) \t" + Math.sqrt( -0.0 ) );
System.out.println("Math.sqrt( 0.0 ) \t" + Math.sqrt( 0.0 ) );

OUT PUT IS

Math.sqrt( -9.0 ) NaN
Math.sqrt( -0.0 ) -0.0 //doubt
Math.sqrt( 0.0 ) 0.0

Thanks
kundan
 
kundan varma
Ranch Hand
Posts: 323
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
Hi All
I got the answer from api which states
"
public static double sqrt(double a)Returns the correctly rounded positive square root of a double value. Special cases:
If the argument is NaN or less than zero, then the result is NaN.
If the argument is positive infinity, then the result is positive infinity.
If the argument is positive zero or negative zero, then the result is the same as the argument.
Otherwise, the result is the double value closest to the true mathetmatical square root of the argument value.
Parameters:
a - a double value.
Returns:
the positive square root of a. If the argument is NaN or less than zero, the result is NaN.
"
THanks
kundan
 
  • Post Reply
  • Bookmark Topic Watch Topic
  • New Topic