Constructor Chaining

[deshdeep divakar]

Hi,
To all,Ranchez could anny buddy clear my doubt the execution
of constructors.ds can b done using this() and super().
Ex

   class Light{
   //Instance variables
   private int noofwatts;
   private boolean indicator;
   private String location;
 
  //Constructors
   Light()
   {
     this(0,false);
     System.out.println("Returning from the Default constructor no.1.");
   }
   Light(int watts,boolean onoffstate)
   {
      this(watts,indicator,"X");
      System.out.println("Returning from Non-Default constructor no.2.");
   }
   Light(int noofwatts,boolean indicator,String location)
   {
      this.noofwatts=noofwatts;
      this.indicator=indicator;
      this.location=new String(location);
      System.out.println("Retuning from Non-Default constructor no.3.");
   }
}
public class Democonscall
{
   public static void main(String args[])
   {
     System.out.println("Creating Light Obj no.1.");
     Light l1=new Light();
     System.out.println("Creating Light Obj no.2.");
     Light l2=new Light(250,true);
     System.out.println("Creating Light Obj no.3.");
     Light l3=new Light(250,true,"DESHDEEP")
   }
}

There is Line written in Book Khalid & Mugal.dt Body of contructor is executed in reverse order.preety confusing plz help out

(added the

tags for formatting code to look like code sort of)
[ March 24, 2005: Message edited by: Barry Gaunt ]

[Mark Spritzler]

First off, under the Add Reply button are ten buttons. One of them is the CODE button which will put CODE tags in your post, where you can paste your code in there and it will remain formated, it will keep its indentation which makes things easier to read.

Mark

[Mark Spritzler]

It prints in reverse order because it calls another constructor first before it does the printouts.

So if you call the no args constructor, it first calls the two arg constructor, which then calls the three args constructor, runs 3's printout, then returns to the 2 arg constructor to its printout of "2", then back to the no args constructor, and there it prints its "1"

Hence, 3 2 1.

Mark

[Thomas De Vos]

I don't think your code compiles, the instance field "indicator" cannot be referred to when you call a constructor of the class:

this(watts,indicator,"X");

Your code would compile when "indicator" is static but that is probably not the intention.
[ March 24, 2005: Message edited by: Thomas De Vos ]

[deshdeep divakar]

Thanks Mark thanks for ur guidance,I will take care of posting
and replying problems from now.