Doubt Regarding wrapper Class.

[Bhalotia Kunal]

Question 9

 

The following code will give
 
1:     Byte b1 = new Byte("127");
2:
3:     if(b1.toString() == b1.toString())
4:        System.out.println("True");
5:     else
6:        System.out.println("False");

A) Compilation error, toString() is not avialable for Byte.
B) Prints "True".
C) Prints "False".


Answer given is - False...

Can any body explain Please...

[Mark Spritzler]

The question is actually about Strings and not a wrapper class.

Since it is using the == instead of the .equals() method, it is checking for objects being the same, pointing to the same point in memory. Not the string's value.

So when you call toString it creates a new String object, so there are two different String objects created in the if statement, and they are not the same, they are not pointing to the same object in memory.

Mark