Dan's Wrapper Class Doubt

[Jas Oberai]

Hi Friends,
The answer for this question is "c",but I am wondering why not "a,c".The two Integer objects i1,i2 are not equal and they might have equal or unequal hashcodes.So(h1 == h2),could return "true" or "false",you never know.Please correct me ..and lemme know where i am going wrong.

class F {
  public static void main (String[] args) {
    Integer i1 = new Integer("1");
    Integer i2 = new Integer("1");
    int h1 = i1.hashCode(), h2 = i2.hashCode();
    StringBuffer sb1 = new StringBuffer("1");
    StringBuffer sb2 = new StringBuffer("1");
    int h3 = sb1.hashCode(), h4 = sb2.hashCode();
    System.out.print((h1==h2)+","+(h3==h4));
}}
 
What is the result of attempting to compile and run the program? 
 
a.  Prints: false,false 
b.  Prints: false,true 
c.  Prints: true,false 
d.  Prints: true,true 
e.  Compile-time error 
f.  Run-time error 
g.  None of the above 
 
Answer :c
 

Thanks in Advance.

[Barry Gaunt]

The two Integer objects i1,i2 are not equal

Are you saying i1.equals(i2) returns false? I suggest you try it.

[Jas Oberai]

Thanks Barry,
After going thru your reply,i understood where i was goin wrong.By saying not equal,i meant that i1,i2 are refering to two different objects on the heap,but i knew i1.equals(i2) is true as the contents were the same.And I was thinking that the hashcode is calculated depending upon the reference i.e "==".Actually,that was my stupidity..sorry!!!