• Post Reply
  • Bookmark Topic Watch Topic
  • New Topic

supersubcatch

 
usha prithvi
Ranch Hand
Posts: 31
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
hi,
In the following code,i am unable to understand the error. can someone expalin me the error.

public class SuperSubCatch {

public static void main(String[] args) {
try{
int a = 0;
int b = 43/a;

}catch(ArithmeticException e){
System.out.println(" generic exception catch ");
}catch (ArithmeticException e){
System.out.println(" this is never reached");
}
}
}

thanks
usha
 
shetal bansal
Ranch Hand
Posts: 63
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
You are catching the same exception twice.If you remove the second catch statement or chanage it to catch(Exception e), the code will work.
 
usha prithvi
Ranch Hand
Posts: 31
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
thankz for ur response
 
  • Post Reply
  • Bookmark Topic Watch Topic
  • New Topic