Help needed.....

[Mohamed Shafi]

code
----------------------------------------

public class kha8 {
int a;
int b;
public void f() {
a = 0;
b = 0;
int[] c = { 0 };
g(b, c);
System.out.println(a + " " + b + " " + c[0] + " ");
}
public void g(int b, int[] c) {
a = 1;
b = 1;
c[0] = 1;
}
public static void main(String[] args) {
kha8 obj = new kha8();
obj.f();
}
}

what will be the output?

a.000
b.001
c.010
d.100
e.101

ans-e.

----------------------

can anyone explain why b's value's is 0 and a's value is retained to 1???


Thanks,

Shafi.

[Lakshmi Prabhakaran]

Hi

 
public class kha8 {
int a;
int b;
public void f() {
a = 0;
b = 0;
int[] c = { 0 };
g(b, c);
System.out.println(a + " " + b + " " + c[0] + " ");
}
public void g(int b, int[] c) {
a = 1;
b = 1;
c[0] = 1;
}
public static void main(String[] args) {
kha8 obj = new kha8();
obj.f();
}
}
 

In method g(int b, int[] c) b refered here is the local variable whereas a is the instance variable. To access a instance variable use this.variableName (this.b) where there is a local variable in the same name.

[Rucha Surve]

Hi,


In the above code, when the method g() is invoked, it is passed instance variable b and array c[]. In the method g() itself there are local variables with the same names as the instance variables b & c[]. so, when you are setting b = 0, you are actually changing the local variable and not the instance variable. But variable a in the method g() is not local coz it has not been declared locally, so when u set "a" to 0 , you are actually changing the instance variable. So the result will be 101.