StringBuffer??

[srikanth reddy]

 class MWC203 {
  public static void main (String[] args) {
    String s1 = new String("ABC"), s2 = new String("ABC");
    StringBuffer sb1 = new StringBuffer(s1);
    StringBuffer sb2 = new StringBuffer(s2);
    boolean b1 = s1.hashCode() == s2.hashCode();
    boolean b2 = sb1.hashCode() == sb2.hashCode();//1
    System.out.print(b1 + "," + b2);
}}
 

my doubt is when there is no method like hashcode in stringbuffer then how come the line 1 is valid??/

please clarify

[Pradeep bhatt]

The method hashcode is defined in the Object which classes implicitly extend.

[Barry Gaunt]

You must understand the concept of inheritance in object oriented languages. A subclass inherits the members of its base class. In the case of StringBuffer (and StringBuilder) you have to be careful because StringBuffer inherits its equals method from Object as well as hashcode.
[ October 22, 2005: Message edited by: Barry Gaunt ]