Thread4

[achayya matta]

please help me whats happening in the following code?

class A extends Thread {
  private static B b = new B();
  private String s1;
  public void run() {System.out.print(b.m1(s1));}
  A(String threadName, String s1) {
    super(threadName); this.s1 = s1;
  }
  public static void main (String[] args) {
    A a = new A("T1","A"), b = new A("T2","B"); a.start(); b.start();
}}
class B {
  private String s1;
  public synchronized String m1(String s) {
    s1 = s;
    try {Thread.sleep(1);} catch (InterruptedException ie) {}
    return "["+Thread.currentThread().getName()+","+s1+"]";
}}

[ November 29, 2005: Message edited by: Mark Spritzler ]

[Lakshmanan Arunachalam]

I think it will print either T1AT2B or T2BT1A not other than that.
Reasons are
1. The reason is object B is shared across two threads and its method is synchronized.
2. Calling sleep method on a thread wont release the lock.
3. We can't be sure that threads will be started in the sequence bywhich their start method is called.
4. Thread schedule algorithm is OS dependent.

Any comments?

[Anup Jadhav]

Hi Lakshmanan,

Your reply seems correct.

Anup