operator n assignment

[pravin kumar]

What is the result that will be printed out
public class Test {
public static void main(String[] args)
{
int a = -8;
int b = ~ -33;
a>>>=b;
System.out.println(a);
}
}

an is -8..am wondering how to work out such questionsPlease guide on this

[Jay Pawar]

Hint:
~ is complement of the number In general
~i = - (i + 1); So, ~10 is equal to -1 * (10 + 1) = -11
Similarly ~-10 = -1 * (-10+1) = 9

Let me know if that works for you.

[pravin kumar]

thnks for the both reply

[Thomas Drew]

pravin kumar
Here is a short program to explain what is happing it it helps.

public class Main {
    
    /** Creates a new instance of Main */
    public Main() {
    }
    
    public static void main(String[] args) {
        int a = -8;  
        int b = ~ -33;
 
System.out.println(" -33 = " + Integer.toBinaryString(-33));
System.out.println("After Conversion ~-33 = " + Integer.toBinaryString(b));
System.out.println("- 8 = " + Integer.toBinaryString(a));
 
System.out.println("Remember only the last 5 digits are used for -33 shift whick is " + Integer.toBinaryString((b&0x0001f)));
System.out.println("Results of  a>>>b :=" + a + " >>> " +(b&0x0001f) + " = " + (a>>>b) + "  " );
 

 
    }
    
}
 

  

The output of the code is :

-33 = 11111111111111111111111111011111
After Conversion ~-33 = 100000
- 8 = 11111111111111111111111111111000
Remember only the last 5 digits are used for -33 shift whick is 0
Results of a>>>b :=-8 >>> 0 = -8