unclosed literal

[achayya matta]

class Char
{
public static void main(String[] args)
{
String s1="\u000a";
String s2="\u000d";
System.out.println(s1+""+s2);
}
}

hai guys, when i ran the program it was saying "unclosed literal:compile error"
can u clarify this thing?
thanks in advance

[Swati Thorve]

Here "\u000a" is a special unicode character,"Linefeed Character" i.e "\n"
therefore
String s1="\u000a";
becomes s1=
;
so nothing is assigned to s & hence it is giving error "unclosed literal:compile error"

same is true for "\u000d" as this is "carriage return" i.e "\r" character
Correct me if i am wrong

Regards
-Swati

[Deepthi Rallabandi]

Hi,

'\u000a' and '\u000d' are Unicode values for "newline" and "carriage return" characters. These values should not be used to represent newline and carriage return in the source code. These values are interpreted as line-terminator characters by the compiler, and will cause compile time errors.

we should use the string literals "\n" and "\r", respectively, for correct interpretation of the characters "\u000a" and "\u000d" in the source code.

[Somasekar Reddy]

Hi,
The compiler translates Unicode characters at the beginning of the compile cycle.

Using the Unicode escape characters \u000A for newline and \u000D for return in a String or comment produces a compile-error as they are interpreted, literally, as 'end-of-line'.

Always use the special characters '\n' or '\r'.


Here is certain special characters which can be represented by escape sequences for your information.

\n \u000A newline
\t \u0009 tab
\b \u0008 backspace
\r \u000D return
\f \u000C form feed


As these are special characters not having any literal value. when you try to convert them to string object compiler checks whether its a valid character or not.Thats why you getting a compiler error.

Please let me know if you need any further assistance in this regard,

Thanks,
Somasekar.