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# Array

Ranch Hand
Posts: 31
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public class test
{
public static void main(String[] agrs)
{
int [][] a1 = { { 1,2,3},{4,5,6},{7,8,9}};
for(int i=0;i<3;i++)
{
for(int j=0;j<3;j++)
{
System.out.println(a1[j][i]);
}
}
}
}

Ans: at run time the values for a1 are
00 -------- 1
01 ---------2
02---------3
Like this we have to get the answer. But output for this question coming as 147258369
Can any one say why this is happening?

Greenhorn
Posts: 26
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The result u r expecting will be printed when u use a1[i][j] instead of a1[j][i]

Sheriff
Posts: 14691
16
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You are using a1[j][i] and incrementing j in the inner loop

So :
a1[0][0] = 1
a1[1][0] = 4
a1[2][0] = 7

Kiran Chand Panga
Ranch Hand
Posts: 31
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I can agree for given answers but While creating the Array I didn�t mention any reference names like i or j. so why complier is assuming like first reference is �i� and second reference is �j� ?

Greenhorn
Posts: 18
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The compiler is not assuming this
The interpreter is assuming this because this
is what you tell him to assume.

With the code you show you are actually going through the table
[1,2,3]
[4,5,6]
[7,8,9]
in the order 1->4->7->2->5->8->3->6->9
while you want to go that way:
1->2->3->4->5->6->7->8->9

Hope this helps.
[ February 15, 2006: Message edited by: Peter Petrov ]

Ranch Hand
Posts: 35
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Summary of two dimensions arrays:
[array][cells]

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