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Why do i get this run time eroor... plz help

 
Anish Nagraj
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Posts: 20
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My program is like this...

public class Propogate {

String reverse(String val) throws Exception{

String reverseStr ="";
System.out.println(val);
if(val.length()== 0){
throw new Exception();
}
else{

for(int i = val.length(); i>0; --i){
reverseStr = reverseStr + val.charAt(i);
}
val = reverseStr;
}
return val;

}
public static void main(String[] args) {

Propogate eh = new Propogate();
try{
System.out.println(eh.reverse("java"));
}catch(Exception e){
System.out.println(e);

}


}
}

i get a ru time error telling

java.lang.StringIndexOutOfBoundsException: String index out of range: 4
 
Keith Lynn
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The first index in a String is position 0. So the last position is not the length of the String, but one less. You are trying to access the position in the String indicated by its length.
 
srilatha kareddy
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for(int i = val.length(); i>0; --i){
reverseStr = reverseStr + val.charAt(i);
}

val.length()=4;

val.charAt(4); ...Its not there so run-time exception occur

...this will work.........
for(int i = val.length()-1; i>=0; --i){
reverseStr = reverseStr + val.charAt(i);
}
 
Anish Nagraj
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Posts: 20
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1. i want to know exactly when the pre-increment of i works out and the value of i becomes 2 in the program i specified.

2. i also want what difference does a pre-decrement and post-decrement in this program makes... hope it makes no difference... let me know the exact description...
 
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