This week's book giveaway is in the Kotlin forum.We're giving away four copies of Kotlin in Action and have Dmitry Jemerov & Svetlana Isakova on-line!See this thread for details.
Win a copy of Kotlin in Action this week in the Kotlin forum!
programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering OS Languages Frameworks Products This Site Careers Other all forums
this forum made possible by our volunteer staff, including ...
Marshals:
Sheriffs:
Saloon Keepers:
Bartenders:

# plz Explain me line by line this code

Ranch Hand
Posts: 46
class Beverage {

boolean [] b = new boolean[3];
int count = 0;

void set(boolean [] x , int i ){
x[i]= true;
++count;
}

public static void main(String []args){
Beverage ba = new Beverage();
ba.set(ba.b,0);
ba.set(ba.b,2);
ba.test();
}

void test() {
if(b[0]&& b[1] | b[2])
count++;
if(b[1] && b[(++count -2)])
count +=7;
System.out.println ("Count =" +count);

}
}

jerry sharma
Greenhorn
Posts: 23
hi Akhilesh
le me do a bit 2 exp
whenn u call the set method first time in main
coun becomes 1
second time it becomes 2

on calling test method
if(b[0]&& b[1] | b[2])
count++;
cond is true
hence

count becomes 3

so in SOP ans should be 3

regards

jerry

Shaliey Gowtham
Ranch Hand
Posts: 104
b[] = new boolean[3] gives the default values "false" to teh three elements

set() modifies the b[0] = b[2] = true;
and the value of count = 2;

so the first condition is ( true && false || true) is "true"
and count is incremented to 3;

Then the next condition is (false && b[++count-2]) evaluates only upto the first false, since "&&" is short circuit and.
So the count remains "3".

If the expression has been (true && b[++count-2]) then the result is "11"
[ April 04, 2006: Message edited by: Shaliey G ]