Constructor overriding

[Binesh Thusantha]

class M{
static String s1 = "M.s1";
static void prints1(){
System.out.print("M.prints1, " + s1+"");
}
M(){
prints1();
}
}
class N extends M{
static String s1="N.s1";
static void prints1(){
System.out.print("N.prints1,    " + s1+"      ");
}
N(){
prints1();
}
public static void main(String [] args){
N n = new N();
}
}

can u explain y this type of output come here? Please explain.....
M.prints1, M.s1N.prints1, N.s1

[Vlado Zajac]

There is no overriding in the code since constructors, static methods and member variables cannot be overriden.

N() first calls M() which calls M.prints1() which uses M.s1 (output: M.prints1, M.s1). Then the body of N() is executed which calls N.prints1() (which prints N.prints1, N.s1).

[Binesh Thusantha]

Thanks for your reply Vlado Zajac.....

Can u explain why does N() call M()

[vidya sagar]

Can u explain why does N() call M()

Whenever a constructor is called,it automatically calls its superclass constructor to finish the process of completing the creation of the object.

We can call it explicility by specifying super()(which makes call to the superclass constructor) otherwise JVM will call implicility.

Note:super() if present,should be the first line inside the constructor.