Why does count not reflect # of tokens?

[Firas Zuriekat]

class Volatile {
public static void main(String [] args) {

String s = "x1234 y56 z7 a";
String [] sa = s.split("\\d");
int count = 0;
for( String x : sa)
count++;
System.out.println("total: " + count);
}
}

What's result?

A) total: 7
B) total: 8
C) Compile error because "volatile" is a keyword

Why is answer B? Why does count not reflect # of tokens?

[ May 30, 2006: Message edited by: Firas Zureikat ]
[ May 30, 2006: Message edited by: Firas Zureikat ]

[Naseem Khan]

Why is answer B? Why does count not reflect # of tokens?

If its not typo mistake i.e. class name is volatile (v small), then correct answer will be C.

Program will not compile.

Regards

Naseem

[wise owen]

x|1|2|3|4 y|5|6 z|7 a|
that is
x|||| y|| z| a

[Naseem Khan]

When digits r used as a delimiter, continguous digits which are connected without a break result in a empty token.

String s = "x1234 y56 z7 a";
String str[]=s.plit("\\d");
 
          12, 23, 34 and 56 are continguous digits will result in empty token ""
str array>>>    {"x", "", "", "", " y", "", " z", " a"}

Naseem

[Firas Zuriekat]

OK, I got it..Thanks.