operators

[lavanya sankuappan]

class c {
public static void main(String[] args) {
int i = 0;
while (++i < args.length) {
System.out.print(args[i]);
}}}

when i run this program like java c abcdef,it doesn't show any output.why is it like that?

[lavanya sankuappan]

i am sorry about that,i didn't leave space between arguments

[Vladimir Scheglov]

When you using while (++i < args.length) first value of i in boolean expression after ++ is 1. When you start program with one argument (like java c arg), program no output. When you start program with two arguments (like java c arg1 arg2), program output without last argument.

Correct code:
class c {
public static void main(String[] args) {
int i = 0;
while (i++ < args.length) {
System.out.print(args[i]);
}}}

[krish bajaj]

hello lavanya
ur program will give an output just try and hey vladimir program must give an exception ArrayIndexoutOfBound
ur program is all right it shows output but leave first element
output:bcdef

krish bajaj

[Siri Naray]

hai lavanya,
you dont get an output because the While test is false so it never goes to the print statement.
While(++i<args.length) ie. 1<1 is false.
Hope this helps

[Pinkal Patel]

Two Topic here coverd
1) Run time Argument will start with 0
2) Pre Increment Operator ++

++i Will increate the i before it will compare.

[Anoop Kavalloor]

Hi,
The prefix increment operator increments the value of the variable first and then uses the variable in the operation[or expression]. Now consider your case when u say ++i<args.length and the command line exp is java c abcd. here args.length will return 1. value of i before the if() loop is zero. when it encounters the line ++i < args.length, it first increments the value of i to 1 and then i takes part in the expression. Now 1 cannot be less than 1 and hence no output is shown.