Which overloaded method?

[Suhas Wadadekar]

  class SuperBase{
public void print(SuperBase sb){System.out.println("Super");}
}
class Base extends SuperBase{
public void print(Base b){
System.out.println("Base");}
}  
class Test{
public static void main(String[] args){
SuperBase sb1 = new SuperBase();
SuperBase b1 = new Base();
Base b2 = new Base();
sb1.print(new SuperBase());
b1.print(new Base());
b2.print(new Base());  // doubt here
}
}

My doubt is which method will be invoked at the indicated line, because class Base has 2 print methods and both can take a Base object as an argument?

[Neelesh Bodas]

[ my previous stupid reply has been deleted ]
When more than one overloaded methods are valid candidates, the "most specific" overloaded method is chosen. Hence the Base version will be chosen, not the SuperBase version.

[Gowher Naik]

According me the Base class contains
two overloaded methods
1.public void print(SuperBase sb){
System.out.println("Super");
}
from SuperBase class
2.public void print(Base b){
System.out.println("Base");
}
from Base class
check code below

class SuperBase{
public void print(SuperBase sb){
System.out.println("Super");
}
}
class Base extends SuperBase{
public void print(Base b){
System.out.println("Base");
}
}  
class Test{
public static void main(String[] args){

Base b2 = new Base();
b2.print(new Base());       // Base class method
b2.print(new SuperBase());  // SuperBase class method
}
}

please correct me if i am wrong.

[wise owen]

gowher: you are right.