Why its not incrementing???

[rimzy abdulkader]

int i=1;

System.out.println(i=i++);
[ October 11, 2006: Message edited by: rimzy abdulkader ]

[Petrus Pelser]

I'm not sure what your problem is, but when I run this code it prints out 2.

So i is incremented.

[rimzy abdulkader]

sorry there was some mistake in the code
try with the new one

[Shaan Shar]

Originally posted by rimzy abdulkader:
sorry there was some mistake in the code
try with the new one

And where is the new one...

[Devidas Menon Aniyath]

 int i=1;
 
System.out.println(i=i++);   

Hi,
Here you are using post increment operator. So i is printed first and then incremented..Try this

  int i=1;
 
System.out.println(i=i++); 
 System.out.println(i);

[Dhinakaran]

Hi
The Operator you have used is post increment operator,
hence you will get incremented value after you finish the sentence.

but you have assigned the unincremented value again to the 'i'...

if you do like this, you may get incremented value.

System.out.println(i= ++i);

regards
dina

[Bauke Scholtz]

Indeed. Summarized:

i++ has an postfix increment operator. When used in an expression, the value of i will be used in the expression first and when the expression is finished, then the value will be incremented.

++i has an prefix increment operator. When used in an expression, the value of i will be incremented first and then the value will be used in the expression.

[Joe San]

Hi all above,

I think some of them are misleading with their answers.

Petrus Pelser

I'm not sure what your problem is, but when I run this code it prints out 2.

So i is incremented.

int i = 1;
System.out.println(i=i++); //prints 1
System.out.println(i=i++); //prints 1
System.out.println(i); //prints 1

and as long as you do post increment of i and assign it to i itself, the new incremented value of i is never going to be assigned to i.

Regards,
Jothi Shankar Kumar. S

[Rajesh Kadle]

Please try it again.

int i = 1;
System.out.println(i=i++); //prints 1
System.out.println(i=i++); //prints 1
System.out.println(i); //prints 1

Output will be: 1 2 3

int i = 1;
System.out.println(i=i++); //prints 1 (i value before increment (1) is the result of the expression, so 1 is printed, after printing i is incremented so i value will be 2)
System.out.println(i=i++); //prints 2 (Same as above, 2 will be result of the expression so 2 is printed and i is incremented, i becomes 3)
System.out.println(i); //prints 3

[ October 13, 2006: Message edited by: Rajesh Kadle ]

[Bijendra S. Rajput]

int i = 1;System.out.println(i=i++); //prints 1System.out.println(i=i++); //prints 1System.out.println(i); //prints 1

out put will be 1 1 1 only.
Reason- we are not assigning the incremented value ot i. So value of i will not change.

[Petrus Pelser]

The message was edited. The first code used pre-increment, thats why my answer was 2.

[Joe San]

Hi Rajesh,

I guess probably you did not compile the program and that you just guess the output to be 1,2 and 3.

Your quote,
code:

int i = 1;
System.out.println(i=i++); //prints 1 (i value before increment (1) is the result of the expression, so 1 is printed, after printing i is incremented so i value will be 2)
System.out.println(i=i++); //prints 2 (Same as above, 2 will be result of the expression so 2 is printed and i is incremented, i becomes 3)
System.out.println(i); //prints 3

You are right that i will be incremented to 2 but that incremented value is never assigned to i which means i still remains 1. Please don't mislead and show me just one java compiler where you get the output 1,2,3 for the above code.

Regards,
Jothi Shankar Kumar. S

[Devidas Menon Aniyath]

Hi Jothi,
Please try the program to run in an Eclipse IDE and run it as a java application.
It will print 1,2,3
But if you are using simlple notepad and console it will print 1,1,1
that's why some has given answers as 1,2,3
Any way,I agree with your opinion that the output will be 1,1,1
and I don't know the reason about the other output

[Barry Gaunt]

In eclipse 3.2 using Java 5.0 it prints 1 1 1.

[Joe San]

Hi Above,

I compiled the program using netBeans 5.0 and I'm getting 1,1,1...It is not dependent on the IDE that we use but rather the concept behind it. According to JLS, the output is 1,1,1. If not this ain't java.

Regards,
Jothi Shankar Kumar. S

[Barry Gaunt]

Originally posted by Jothi Shankar Kumar Sankararaj:
It is not dependent on the IDE that we use but rather the concept behind it. According to JLS, the output is 1,1,1. If not this ain't java.

Most of us agree with you. But some are getting 1,2,3 - it's of interest to find out why.

[Joe San]

Hi Barry,

Could that be the problem with the IDE? When you try to run the same program from the command prompt, it gives correct results as 1,1,1 which is unanimous for the above program.

Regards,
Jothi Shankar Kumar. S

[Barry Gaunt]

No, I get the expected values 1 1 1 with Eclipse. I suspect that the ones getting 1 2 3 are running the wrong code.

[Flávio Albuquerque Camilo]

Try to run this code and you'll see the results:

public class IncrementTest {
 
public static void main(String[] args) {
int i = 1;
int j = 1;
 
System.out.println(i = i++);
System.out.println(i = i++);
System.out.println(i);
 
System.out.println();
 
System.out.println(j++);
System.out.println(j++);
System.out.println(j);
}
 
}

I think that after this example, there's no doubt anymore.

[yogesh sood]

Hi Fl�vio ,

Thanks for posting code, so now there is distinction between 2 set of results.

However, it would be really helpful if some one can shed some light on fact that why we are getting 1 ,1 ,1 as result for first set.

My doubt is if we say x=i++; then value of i is incremented after expression evaluation and assigned to i.

However , when we say i=i++; then value of i should be incremented after expression evaluation and should be assigned to i. I am unable to figure out why post increment of value of i is not visible. I thought we will have one copy of i in memory so if that get updated with new value of i it should have been reflecting.

I think im unable to figure out in which order assignment and increment will be handle at runtime. Please provide some hints.

Thanks

[Barry Gaunt]

For those who do not believe that

int i = 0;
i = i++;

results in i still being 0, I recommend reading Corey's Tipline article on Postincrement with Assignment.

[William Yan]

I tried this,

public class Test {
public static void main(String... strings) {
int i = 1;
System.out.println(i = i++);
System.out.println(i = i++);
System.out.println(i);
}
}

OMG, i really got "1,2,3" in eclipse3.1 with jdk5, and "1,1,1" in Console. Who can drop me a light!!!

[Joe San]

Hi Above,

That should be a problem with the IDE. Is there anyone who can get this striaght?

Regards,
Jothi Shankar Kumar. S

[William Yan]

i appreciate that, Jothi
and i even got output "0" running this on my IDE

    int i = 0;
    i = i++;
    System.out.println(i);

which seems to be correct while i got "0,1" running this on my IDE

    int i = 0;
    System.out.println(i = i++);
    System.out.println(i);

It seems to be a problem of System.out.println(); in my Eclipse.

[Rajesh Kadle]

Hi all,

Sorry for the late reply.

I am using Eclipse and Java 5.0. If you try the following code, as expected it is printing 1,1. Its printing 1,2 only when we include this assignment inside the 'println'.

int i = 1;
i = i++;
System.out.println(i); // prints 1
i = i++;
System.out.println(i); // prints 1
                System.out.println(i); // prints 1

int i = 1;
System.out.println(i = i++ ) ; // prints 1
System.out.println(i = i++ ) ; // prints 2
                System.out.println(i); // prints 3

I dont know why this is happening
[ October 16, 2006: Message edited by: Rajesh Kadle ]

[Joe San]

Hi William and Rajesh,

I tried this on my system and I use netBeans 5.0,

[B]public class Main {
   
public static void main(String args[]){
         int i = 0;
    System.out.println(i = i++);
    System.out.println(i);
    System.out.println(i = i++);
    System.out.println(i = i++);
    System.out.println(i = i++); 
    System.out.println(i = i++); 
    System.out.println(i = i++); 
    System.out.println(i = i++);
    System.out.println(i);
 i=i++;
    System.out.println(i);
       
  }
} 
       
 [/B]

And Im getting the output as below,

compile-single:
run-single:
0
0
0
0
0
0
0
0
0
0
BUILD SUCCESSFUL (total time: 0 seconds)

As you can see above...it just gives me 0 and nothing else.

Regards,
Jothi Shankar Kumar. S

[Bauke Scholtz]

I cannot reproduce the weird behaviours?

public class Test {
 
    public static void main(String[] args) {
        int i = 1;
        int j = 1;
 
        System.out.println(i = i++);
        System.out.println(i = i++);
        System.out.println(i);
 
        System.out.println();
 
        System.out.println(j++);
        System.out.println(j++);
        System.out.println(j);
    }
}

WebSphere Studio Application Developer 5.1.1 IE (Eclipse 3.1.2 + JRE 1.4.2) prints:

1
1
1
 
1
2
3

ObjectWeb Lomboz (Eclipse 3.2 + JRE 1.5.0) prints:

1
1
1
 
1
2
3

Command console (JDK 1.5.0) prints:

C:\>javac Test.java
 
C:\>java Test
1
1
1
 
1
2
3
 
C:\>

Command console (JDK 1.4.2) prints:

C:\>javac Test.java
 
C:\>java Test
1
1
1
 
1
2
3
 
C:\>

You're [s]all[/s] doing something wrong?
[ October 16, 2006: Message edited by: Bauke Scholtz ]

[Barry Gaunt]

@Bauke: "You're all doing something wrong?"

Only one (or is it two) posters are getting the wrong answer. I reckon they are not running the correct code somehow.

[Bauke Scholtz]

Sorry, I was goaling on William + Rajesh indeed.

[Rajesh Kadle]

Hi,

When i tried from command console (JDK 1.4) i got the desired out put of (1 1 1) but when i tried it from Eclipse i got (1 2 3).

[Barry Gaunt]

@Rajesh,
Can you delete your Eclipse project completely (delete all code and compiled classes) and start from scratch. Post the complete class you are running, not just the code in question. What Eclipse version are you using?

I just cut and pasted your code into Eclipse 3.2 and it works correctly (1 1 1). Even when using Eclipse's scratchpad to execute the code I get the same result (1 1 1).

I get the same (1 1 1) with Eclipse 3.1.2.
[ October 16, 2006: Message edited by: Barry Gaunt ]

[Rajesh Kadle]

Hi Barry,

I created a new project and created the following program and ran the code. I am using eclipse version 3.1.0 and my Eclipse JDK compliance settings are as below:

Compiler Compliance Level : 1.4
Use default compliance settings: checked
Generated .class files compatibility: 1.2
source compatibility: 1.3

Code: Increment.java

public class IncrementTest{
public static void main(String[] args) {
int i=1;
System.out.println(i=i++);
System.out.println(i=i++);
System.out.println(i);
i=1;
i=i++;
System.out.println(i);
i=i++;
System.out.println(i);
System.out.println(i);
}
}

Output:

1
2
3
1
1
1

In my colleague's machine with same Eclipse compliance settings, above program is showing the desired output of (1 1 1). I am not sure what is causing this, am extremely sorry for wasting rancher's valuable time. I will try to figure what is wrong with me (my pc).
[ October 16, 2006: Message edited by: Rajesh Kadle ]

[William Yan]

my Eclipse is
Eclipse SDK
Version: 3.1.0
Build id: I20050627-1435

and i tried this

public class Test {
public static void main(String argv[]) {
int i = 0;
System.out.println(i = i++);
System.out.println(i);
}
}

on my computer and !another computer!, both output "0,1".
but in the console, it output "0,0". CORRECTLY.
i dunno WHY.

[Barry Gaunt]

Ok, on Eclipse 3.1.2 it's all ones.
So it is a bug in the old Eclipse 3.1.0 version. Eclipse has its own compiler, it does not use the standard compiler from Sun. Perhaps some optimization is not working correctly. Maybe someone who has the time can search through Eclipse's bug list.

So you guys with the "funny" answer (1 2 3) better upgrade your Eclipse IDE.

[Barry Gaunt]

One of my collegues at work came up with this Eclipse Bug Report

[William Yan]

i downloaded eclpise 3.2.
and..
..the answer is CORRECT!
thanks to Jothi and Barry.

[Rajesh Kadle]

Thanks all.

[Joe San]

Hi William,

The point here is that you understood the logic finally. All the credit goes to Barry.
Congrats Barry and thanks for bringing this long post to an end.

Regards,
Jothi Shankar Kumar. S
[ October 16, 2006: Message edited by: Jothi Shankar Kumar Sankararaj ]