Method calling

[sentil kumar]

public class vararg {
static void show(int ... a) {
System.out.println("varchar ---"+a[0]);
}

static void show(Object o,Object o1) {
System.out.println(o);
}
public static void main(String[] args) {
show(1,2);
}
}

please explain how the method show(Object o,Object o1 ) is called for show(1,2).

[Valentin Mone]

Hi,
Boxing will always be chosen over varargs...that's why show(Object o,Object o1 )is called.
widening beats boxing and varargs, and boxing beats varargs. In your case int is boxed to Integer...than widened to Object. Hope this helps you.
[ November 13, 2006: Message edited by: Valentin Mone ]

[Sanjeev Singh]

Sentil,
Remember the rule,
[*]boxing beats varargs
[*]widening beats varargs
So,varargs gets the chance only when there is no methods with matching parameters with the callee.
[ November 13, 2006: Message edited by: Sanjeev Kumar Singh ]