The answer is A, B, E and F (correct me if you disagree!)
A: b2[0][1] refers to a 2d array, which b is.
B: b[0][0] refers to a byte value, which b3 is.
E: b2[0][1][0][0] refers to a single byte value, as does b[0][0]
F: b2[0][1] refers to a 2d array, which 'big' is.
C: b2[1][1][0] refers to a 1d array, whereas b[0][0] refers to a single byte
D: b2[1][2][0] refers to a 1d array, whereas b is a 2d array
If you can't just see the number of dimensions when looking at the code you could look at an array like this:
byte b2 [][][][] = new byte [2][3][1][2]; //a 4d array
If you put:
b2[0][1][0][0] you're referring to a single value
b2[0][1][0] you're referring to a 1d array
b2[0][1] you're referring to a 2d array
b2[0] you're referring to a 3d array
b2 you're referring to a 4d array
Notice the
pattern - so you could apply this to other arrays:
e.g
byte [][] b = new byte [2][1]; //a 2d array
b[0][0] single value
b[0] 1d array
b 2d array
There might be easier ways of working this out but I think once you're familiar with working with arrays (through practise) it's like doing timestables and the answer is obvious.
[ November 27, 2006: Message edited by: Andy Morris ]
