varargs doubt

[Carlos G�mez]

hi ranchers,

what is the difference between the next methods ?

public void method1(int... a){} // 1
public void method2(int[]... a){} // 2
public void method3(int... a[]){} // 3

why method "method3" does not compile ?

Thanks in advance

[Barry Gaunt]

After the "..." must follow a parameter name. The parameter's type must come before the "...". So (int... a[]) is illegal. The legacy inherited from C of writing [] after the parameter name does not work for var args.

So (int... a) means an indefinite list of ints presented in an array int a[],
(int[]... a) means an indefinite list of int arrays presented in an array int[][] a)

Try this:

public class VarArgs
{
    static void m(int... a) {
        System.out.println("m: " + (a instanceof int[]));
    }
    
    static void m1(int[]... a) {
        System.out.println("m1: " + (a instanceof int[][]));
    }
    
//    static void m2(int... a[]) { // compile error: ')' expected after a
//        System.out.println("m: " + (a instanceof int[]));
//    }
    
    public static void main(String[] args) {
        m(); m1();
    }      
}    

[ December 08, 2006: Message edited by: Barry Gaunt ]

[Carlos G�mez]

thanks a lot Barry