please explain This Code

[Akhilesh Yadav]

abstract class D {String s1 = "D";
String getS1()
{return s1;}}
class E extends D {String s1 = "E";
String getS1()
{return s1;}}
class F {
public static void main (String[] s) {
D x = new E();
System.out.print(x.s1 + x.getS1());
}}

I was Expecting EE output
but the output is DE
please Explain How

[Anthony Karta]

Originally posted by Akhilesh Yadav:
abstract class D {String s1 = "D";
String getS1()
{return s1;}}
class E extends D {String s1 = "E";
String getS1()
{return s1;}}
class F {
public static void main (String[] s) {
D x = new E();
System.out.print(x.s1 + x.getS1());
}}

I was Expecting EE output
but the output is DE
please Explain How

Just remember that variable is determined during compile time (instance x is type D) and which method get invoke is determined during runtime (the actual object is type E as you expected). hth.

[Joe San]

The o/p is quite obvious. Run time polymorphism is only for methods and not instance variables. Which variable called will depend on the reference type at compile time. Hence the O/P DE.

[Harish Paravasthu]

Variable depened upon the instance where as Method depends upon the Type of Object created.
So here the instance is of Type D, which outputs the s1 as "D" . Object Type is of E,which calls the method in it,takes the instance variable of it,that is s1 as "E" and so prints E.
Hope your dount got cleared.

Thanks
Harish