Confusion in overloaded constructors

[kumar shinde]

Consider the following code :


public class Three
{
float f;
Three()
{
this(5);
System.out.println("In No arg type" + f);
System.out.println("In No arg type" + this.f);
}


Three(float f)
{

System.out.println("In Arguments type" + f); // output is 5.0
System.out.println("In Arguments type" + this.f); //output is 0.0
}

public static void main(String args[])
{
Three t = new Three();
}
}


Can anyone please explain why the output for first println statement is coming 5.0 and the secong one ( call to this.f ) results to 0.0 why does the value for two statement is not 5.0 ?
why does the value for (this.f) is not set to 5.0 ?

[Rohan Pujari]

f in Three(float f) is the local copy of f but when you refer to this.f it refers to the class variable f whose value is 0 as it is not initialized. the f in Three(float f) hides the class variable f.

[Shashi Kant]

Hi Kumar

to set the this.f to 5.0 you have to use this.f = f; in constructor Three(float f).

Three(float f)
{
this.f = f;
System.out.println("In Arguments type" + f); // output is 5.0
System.out.println("In Arguments type" + this.f); //output is 0.0
}

By doing this you will get all the output values for f as 5.0.
For constructor Three(float f) , the f is local variable, whose scope is limited to the constructor[Three (float f)] only.


Regards
Shashikant

[kumar shinde]

Thank-you very much Roohan & Shashikant.... now I understand it perfectly ...