Array initialization - doubt

[raja kanak]

    
class Test
{
   public static void main(String[] args)
   {
      int i = 4;
      int ia[][][] = new int[i][i = 3][i];    //1
      System.out.println( ia.length + ", " + ia[0].length+", "+ ia[0][0].length);
   }
}

When compile & run the above code gives 4,3,3 But I can't understand the logic. Im satisfied with 4 but how came 3,3?

Right side of = in expression //1, in place of i=3, can we call a function which returns an int?

[vivekkumar sharma]

hi ,

yes it works with function as well. I had an impression that dimension of an array shall be compile type constant but following program compile and runs fine,May be i was confusing with C++.

  
import java.util.*;
class Test{   
public static void main(String[] args)   {  
int i  = Integer.parseInt(args[0]);
    
int ia[][][] = new int[i][new Test().myFunc(i)][i];   
//1     
System.out.println( ia.length + ", " + ia[0].length+", "+ ia[0][0].length); 
  
} 
 
public  int myFunc(int j){
int i=3;
return j*i;
}
}