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Whats the Output. of this.....?
byte b = -13;
b >>>= 1;
System.out.println(b);
Shift operator not on the 310-055 exam!

Anyways I think you are going for 1.4.

Here you go!

Let us see what output comes:

(11110011) = -13 (2's complement representation of -13)

-13 >>> 1
(11111001) = -7 (2's complement representation of -7)

So the output is -7

Got it Manoj?

Regards,
cmbhatt
[ April 20, 2007: Message edited by: Chandra Bhatt ]
I dont think its the right answer....
>>> is unsigned right hift operator
Hi John,

I would like to know the correct answer. How >>> operator works.
Although it is not on the exam (310-055).

>>> Shift right, filling with zeros from left;

Regards,
cmbhatt
byte b = -42; // 1101 0110
int result = b >>> 4; // 268435453

It is instructive to compare the value of the expression (-42 >>> 4) with that of the expression (-42 >> 4), which has the value -3. The byte value for b, after unary numeric promotion to int, is shifted right with zero-fill four places.

b >>> 4
= 1111 1111 1111 1111 1111 1111 1101 0110 >>> 4
= 0000 1111 1111 1111 1111 1111 1111 1101
= 0x0ffffffd
= 268435453

But in the asked question since we are using an assigment operator the casting is done by the operator implicitly so
0111 1111 1111 1111 1111 1111 1111 1001 the higher order bits are dropped
and what results is 1111 1001 which is -7.
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