return type

[Prahlad Joshi]

this is a question from geocities.com/ganesh30/
class NewClass{

static int tomb( char a){
throw new NumberFormatException();
}

public static void main(String args[]){
try
{
tomb('a');
}
catch (Exception e)
{
System.out.println("Done");
}
}
};
even if the tomb function is not returning any thing(it is declared to return integer )there is no compiler error. why?
[ April 23, 2007: Message edited by: Prahlad Joshi ]

[Chandra Bhatt]

class NewClass{
 
    static int tomb( char a){
        throw new NumberFormatException();
    }
 
public static void main(String args[]){
try {
    tomb('a');
}catch (Exception e) {
    System.out.println("Done");
}
}
};

Prahlad says,
even if the tomb function is not returning any thing(it is declared to return integer )there is no compiler error. why?

Because compiler is smart enough to understand the case when you type anything after the line:

throw new NumberFormatException();
//any statement even return is not reachable

If you put any thing after the throw ..., compiler will complaint that
... line is not reachable.


BTW, Welcome to JavaRanch!

Regards,
cmbhatt

[Prahlad Joshi]

i am not getting .when a function has a return type it must have to return that type or covarinat one otherwise compiler gives an error.

[anil kumar]

hi
Prahlad Joshi

---------------------------------------------------------------------
when a function has a return type it must have to return that type or covarinat one otherwise compiler gives an error
--------------------------------------------------------------------

it is correct if your code does not contains

throw new NumberFormatException();

the above statement.

If you put any statement after to that ,then you will get compaile time error.

Because at run time after executing the throw statement.The contol will go to the method which call's this method.

The compiler will know that the statements after to throw won't execute.
I think you have understood.