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Can you guess the output without compiling?

 
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(Fixed the code after Barry's comments)
[ May 07, 2007: Message edited by: M Krishnan ]
 
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It will give an error because the constructor is private
 
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Hi Shyam,

I think you need to see the var-arg which is allowed since Java 5.0;

1- void method1(String... args) {}
2- void method1(int x,String... arg) {}

Both are legal and compile fine.

In Krishnan's question, the compiler error comes because the constructor is private as already pointed by Ravi.

Thanks,
[ May 06, 2007: Message edited by: Chandra Bhatt ]
 
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Originally posted by praveen oruganti:
I think it will show error because in the code for abs1() method is declared as private.



abs1() is not a method it is a constructor. This is a bad coding example because it is not using the standard Java convention of using an uppercase letter to start class names and constructors.
 
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it won't compile..you are creating an instance of an abstract class explicitly dude..:-)
 
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Suhaas,
could you please read the Naming Policy and change your name accordingly ? Thank you
 
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Originally posted by Suhaas UNDEFINED:
it won't compile..you are creating an instance of an abstract class explicitly dude..:-)



Abstract class can't be instantiated. But there is no such case in that code. See what is after new operator. Is it instantiation of the abstract class or abstract class ref variable refers to the object of the subclass?


Polymorphic assignment.


Thanks,
 
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its throwing this error
"Implicit super constructor Abs1() is not visible for default constructor. Must define an explicit constructor"

which is pefectly fine as per expectation
 
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