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Doubt in System.out.println code

 
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Hi

I have this small piece of code

for(byte b = 1;b>0;b++)
System.out.println(b);


What will be the output?

output:
1-127

My question is - why it is not throwing error at run time after 127 value?
 
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Hi Gunjan,
Its because when it reaches its maximum size it will get incremented and again it goes back to its minimum size.



Regards
NIK
SCJP 1.5
 
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When b=127,because b is byte type,its size is 8 bit,so b=11111111,when b+1
it become 00000000,then b>0 is false, then it quite the loop.

The result is print 1-127.

If i make some mistake,please correct .
 
Gunjan Kumar
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ok

I got it

So after 127, it will start from -128

Thanks
 
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Hi Zhao,

your guess is close to the correct answer.

127 in binary is 01111111. If you add one you get 10000000 which is -128.
 
Zhao zhenhua
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hi,Manfred ,yes ,you are right. ,Thank you!
 
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