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doubt on char default value...

 
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Hi,

I am little confused how the "ch" value is being calculated at #2,#3.
When I print the "ch" value at #1, it prints nothing.

My doubt is when i print ba[ch] at#3 it should take as ba[null].Not
sure how it is taking the index value for ch is 0 and printing false.

I know that the default value for char is \u0000 (null character).

Any inputs?? Thanks..

import static java.lang.System.*;
public class TestClass12
{
static boolean b;
static int[] ia = new int[1];
static char ch;
static boolean[] ba = new boolean[1];

public static void main(String args[]) throws Exception
{
out.println(" ch :"+ch);//1
boolean x = false;
if( b )
{
out.println("1");
x = ( ch == ia[ch]);
}
else x = ( ba[ch] = b );//2
System.out.println(x+" "+ba[ch]);//3
}
}
 
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Originally posted by Konda Golamaru:
...My doubt is when i print ba[ch] at#3 it should take as ba[null]. Not sure how it is taking the index value for ch is 0 ...


A Java char is really a numeric value that corresponds to a character symbol (see ASCII table). The "null char" has a numeric value of zero. A Java int can obviously have a zero value, but it does not have a "null" value.

An array index is an int. So in the expression ba[ch], ch is converted to type int with a numeric value of zero.
[ June 09, 2007: Message edited by: marc weber ]
 
Konda Golamaru
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Hi Marc,

Thank You. I think I am clear now.

--Konda Golamaru.
 
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